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How to determine the distance to the horizon. Visible horizon and its range. Distance to visible horizon |
The visible horizon, in contrast to the true horizon, is a circle formed by the points of contact of the rays passing through the observer's eye tangentially to the earth's surface. Imagine that the observer's eye (Fig. 8) is at point A at a height BA=e above sea level. From point A, one can draw an infinite number of rays Ac, Ac¹, Ac², Ac³, etc., tangent to the surface of the Earth. The points of contact c, c¹ c² and c³ form a circle of a small circle. The spherical radius Вс of a small circle with с¹с²с³ is called the theoretical range of the visible horizon. The value of the spherical radius depends on the height of the observer's eye above sea level. So, if the observer's eye is at point A1 at a height BA¹ = e¹ above sea level, then the spherical radius Bc" will be greater than the spherical radius Bc. To determine the relationship between the height of the observer's eye and the theoretical range of its visible horizon, consider the right triangle AOc: Ac² \u003d AO² - Os²; AO = OB + e; OB=R, Then AO = R + e; Os = R. Due to the insignificance of the height of the observer's eye above sea level in comparison with the dimensions of the Earth's radius, the length of the tangent Ac can be taken equal to the value of the spherical radius Bc and, denoting the theoretical range of the visible horizon through D T, we obtain D 2T = (R + e)² - R² = R² + 2Re + e² - R² = 2Re + e²,
Given that the height of the observer's eye e on ships does not exceed 25 m, a 2R = 12 742 220 m, the ratio e/2R is so small that it can be neglected without compromising accuracy. Hence, since e and R are expressed in meters, then Dt will also be in meters. However, the actual range of the visible horizon is always greater than the theoretical one, since the beam coming from the observer's eye to a point located on the earth's surface is refracted due to the uneven density of the layers of the atmosphere along the height. In this case, the beam from point A to c does not go along the straight line Ac, but along the curve ASm "(see Fig. 8). Therefore, to the observer, the point c appears to be visible in the direction of the tangent AT, i.e., raised by an angle r \u003d L TAc , called the angle of the earth's refraction. The angle d \u003d L HAT is called the inclination of the visible horizon. And in fact, the visible horizon will be a small circle m", m "2, mz", with a slightly larger spherical radius (Bm "\u003e Bc). The value of the earth's refraction angle is not constant and depends on the refractive properties of the atmosphere, which change with temperature and humidity, the amount of suspended particles in the air. Depending on the time of year and the date of the day, it also changes, so the actual range of the visible horizon compared to the theoretical one can increase up to 15%. In navigation, an increase in the actual range of the visible horizon compared to the theoretical one is taken by 8%. Therefore, denoting the actual, or, as it is also called, geographical, range of the visible horizon through D e , we get: To get De in nautical miles (assuming R and e in meters), the earth's radius R, as well as the height of the eye, e, is divided by 1852 (1 nautical mile equals 1852 m). Then To get the result in kilometers, enter a multiplier of 1.852. Then to facilitate calculations to determine the range of the visible horizon in Table. 22-a (MT-63) shows the range of the visible horizon depending on e, in the range from 0.25 to 5100 m, calculated by formula (4a). If the actual height of the eye does not match the numerical values indicated in the table, then the range of the visible horizon can be determined by linear interpolation between two values close to the actual height of the eye. Range of visibility of objects and lightsThe visibility range of the object Dn (Fig. 9) will be the sum of two ranges of the visible horizon, depending on the height of the observer's eye (D e) and the height of the object (D h), i.e.It can be determined by the formula where h is the height of the landmark above the water level, m. To facilitate the determination of the visibility range of objects, use the table. 22-c (MT-63), calculated by formula (5a): To determine from this table from what distance an object will open, it is necessary to know the height of the observer's eye above the water level and the height of the object in meters. The visibility range of an object can also be determined by a special nomogram (Fig. 10). For example, the height of the eye above the water level is 5.5 m, and the height h of the sign is 6.5 m, in order to determine D n, a ruler is applied to the nomogram so that it connects the points corresponding to h and e on the extreme scales. The point of intersection of the ruler with the middle scale of the nomogram will show the desired visibility range of the object D n (in Fig. 10 D n = 10.2 miles). In navigation manuals - on maps, in sailing directions, in descriptions of lights and signs - the visibility range of objects DK is indicated at an observer's eye height of 5 m (on English maps - 15 feet). In the case when the actual height of the observer's eye is different, it is necessary to introduce the correction AD (see Fig. 9).
Example. The visibility range of the object indicated on the map is DK = 20 miles, and the height of the observer's eye is e = 9 m. Determine the actual visibility range of the object D n using Table. 22-a (MT -63). Decision. At night, the visibility range of a fire depends not only on its height above the water level, but also on the strength of the light source and on the discharge of the lighting apparatus. Usually, the lighting apparatus and the strength of the light source are calculated in such a way that the visibility range of the fire at night corresponds to the actual range of visibility of the horizon from the height of the fire above sea level, but there are exceptions. Therefore, the lights have their own "optical" range of visibility, which may be greater or less than the range of visibility of the horizon from the height of the fire. Navigation manuals indicate the actual (mathematical) range of visibility of lights, but if it is greater than the optical one, then the latter is indicated. The visibility range of coastal signs of the navigation situation depends not only on the state of the atmosphere, but also on many other factors, which include: A) topographic (determined by the nature of the surrounding area, in particular, the predominance of a particular color in the surrounding landscape); B) photometric (brightness and color of the observed sign and the background on which it is projected); C) geometric (distance to the sign, its size and shape). Synonyms: firmament, outlook, sky, skyscraper, sunset of the sky, eyes, eyes, veil, close, mischief, see, look around. Distance to visible horizon
where d and h in kilometers or where d in kilometers and h in meters. Below is the distance to the horizon when viewed from various heights:
To facilitate calculations of the horizon range depending on the height of the observation point and taking into account refraction, tables and nomograms have been compiled. The actual values of the range of the visible horizon can differ significantly from the tabular ones, especially at high latitudes, depending on the state of the atmosphere and the underlying surface. Raising (lowering) the horizon refers to phenomena related to refraction. At positive refraction the visible horizon rises (expands), geographical range the visible horizon increases compared to geometric range, objects are visible that are usually hidden by the curvature of the Earth. Under normal temperature conditions, the rise of the horizon is 6-7%. With increasing temperature inversion, the visible horizon can rise to the true (mathematical) horizon, the earth's surface, as it were, straightens out, becomes flat, the visibility range becomes infinitely large, the radius of beam curvature becomes equal to the radius of the globe. With an even stronger temperature inversion, the apparent horizon will rise above the true one. It will seem to the observer that he is at the bottom of a huge basin. Because of the horizon, objects that are far beyond the geodetic horizon will rise and become visible (as if floating in the air). In the presence of strong temperature inversions, conditions are created for the appearance of superior mirages. Large temperature gradients are created when the earth's surface is strongly heated by the sun's rays, often in deserts and steppes. Large gradients can occur in middle and even high latitudes on sunny summer days: over sandy beaches, over asphalt, over bare soil. Such conditions are favorable for the occurrence of inferior mirages. At negative refraction the visible horizon decreases (narrows), even those objects that are visible under normal conditions are not visible. By the way: space horizon(particle horizon) is both a mentally imaginary sphere with a radius equal to the distance that light has traveled during the existence of the Universe, and the entire set of points of the Universe located at this distance. Visibility rangeIn the figure on the right, the visibility range of an object is determined by the formula , where - visibility range in kilometers, For an approximate calculation of the visibility range of objects, the Struisky nomogram is used (see illustration): on the two extreme scales of the nomogram, points are marked corresponding to the height of the observation point and the height of the object, then a straight line is drawn through them and at the intersection of this straight line with the average scale, the object visibility range is obtained. On nautical charts, in sailing directions and other navigational aids, the visibility range of beacons and lights is indicated for an observation point height of 5 m. If the height of the observation point is different, then a correction is introduced. Horizon on the Moon
Horizon visibility range The line observed in the sea, along which the sea, as it were, connects with the sky, is called visible horizon of the observer. If the observer's eye is at a height eat above sea level (ie. BUT rice. 2.13), then the line of sight going tangentially to the earth's surface defines a small circle on the earth's surface aa, radius D. Rice. 2.13. Horizon visibility range This would be true if the Earth were not surrounded by an atmosphere. If we take the Earth as a ball and exclude the influence of the atmosphere, then from a right-angled triangle OAa follows: OA=R+e Since the value is extremely small ( for e = 50m at R = 6371km – 0,000004 ), then we finally have: Under the influence of the earth's refraction, as a result of the refraction of the visual beam in the atmosphere, the observer sees the horizon further (in a circle centuries). (2.7) where X- coefficient of terrestrial refraction (» 0.16). If we take the range of the visible horizon D e in miles, and the height of the observer's eye above sea level ( eat) in meters and substitute the value of the Earth's radius ( R=3437,7 miles = 6371 km), then we finally obtain a formula for calculating the range of the visible horizon (2.8) For example: 1) e = 4 m D e = 4,16 miles; 2) e = 9 m D e = 6,24 miles; 3) e = 16 m D e = 8,32 miles; 4) e = 25 m D e = 10,4 miles. According to formula (2.8), table No. 22 "MT-75" (p. 248) and table No. 2.1 "MT-2000" (p. 255) according to ( eat) from 0.25 m¸5100 m. (see table 2.2) Range of visibility of landmarks at sea If an observer whose eye height is at a height eat above sea level (ie. BUT rice. 2.14), observes the horizon line (i.e. AT) on distance D e(miles), then, by analogy, and from a landmark (i.e., B), whose height above sea level hM, visible horizon (ie. AT) is observed at a distance Dh(miles). Rice. 2.14. Range of visibility of landmarks at sea From fig. 2.14 it is obvious that the range of visibility of an object (landmark) having a height above sea level hM, from the height of the observer's eye above sea level eat will be expressed by the formula: Formula (2.9) is solved using table 22 "MT-75" p. 248 or Table 2.3 "MT-2000" (p. 256). For example: e= 4 m, h= 30 m, D P = ? Decision: for e= 4 m® D e= 4.2 miles; for h= 30 m® D h= 11.4 miles. D P= D e + D h= 4,2 + 11,4 = 15.6 miles. Rice. 2.15. Nomogram 2.4. "MT-2000" Formula (2.9) can also be solved using Apps 6 to "MT-75" or nomograms 2.4 "MT-2000" (p. 257) ® fig. 2.15. For example: e= 8 m, h= 30 m, D P = ? Decision: Values e= 8 m (right scale) and h\u003d 30 m (left scale) we connect with a straight line. The point of intersection of this line with the average scale ( D P) and gives us the desired value 17.3 miles. ( see table. 2.3 ). Geographic range of visibility of objects (from Table 2.3. "MT-2000") Note: The height of the navigational landmark above sea level is selected from the navigational manual for navigation "Lights and Signs" ("Lights"). 2.6.3. Range of visibility of the landmark light shown on the map (Fig. 2.16) Rice. 2.16. Beacon light visibility ranges shown On nautical nautical charts and in navigation aids, the range of visibility of the landmark light is given for the height of the observer's eye above sea level. e= 5 m, i.e.: If the actual height of the observer's eye above sea level differs from 5 m, then to determine the visibility range of the landmark fire, it is necessary to add to the range shown on the map (in the manual) (if e> 5 m), or subtract (if e < 5 м) поправку к дальности видимости огня ориентира (DD K) shown on the map for the height of the eye. (2.11) (2.12) For example: D K= 20 miles, e= 9 m. D O = 20,0+1,54=21,54miles then: DO = D K + ∆ D To = 20.0+1.54 =21.54 miles Answer: D O= 21.54 miles. Tasks for calculating visibility ranges A) the visible horizon ( D e) and landmark ( D P) B) Lighthouse opening fire findings 1. The main ones for the observer are: a) planes: The plane of the true horizon of the observer (pl. IGN); The plane of the true meridian of the observer (pl. IMN); The plane of the first vertical of the observer; b) lines: The plumb line (normal) of the observer, Line of the true meridian of the observer ® noon line N-S; Line E-W. 2. Direction counting systems are: Circular (0°¸360°); Semicircular (0°¸180°); Quarter (0°¸90°). 3. Any direction on the surface of the Earth can be measured by an angle in the plane of the true horizon, taking the line of the true meridian of the observer as the origin. 4. True directions (IR, PI) are determined on the vessel relative to the northern part of the true meridian of the observer, and KU (heading angle) - relative to the bow of the longitudinal axis of the vessel. 5. Range of the visible horizon of the observer ( D e) is calculated by the formula: . 6. The visibility range of a navigational landmark (daytime in good visibility) is calculated by the formula: 7. Range of visibility of the fire of a navigational landmark, according to its range ( D K) shown on the map is calculated by the formula: , where . In conditions of ideal visibility, that is, standing in an open area, an absolutely flat plain, without grass and trees, in the absence of fog and other atmospheric phenomena, a person of average height sees the horizon at a distance of about 4-5 kilometers. If you rise higher, then the horizon line will move away, if, on the contrary, go down to the lowland, then the horizon will become much closer. there is a special formula that allows you to calculate the distance to the horizon, but I don’t think it’s worth doing, because in each case it will be different. The shortest distance to the horizon will be in the city - usually to the wall of the nearest house. In fact, how subjective the horizon is from us depends on what kind of landscape, mountains, desert, or even water, as well as conditions like precipitation, fog, and so on. But nevertheless, there is a formula that is designed to calculate the distance to the horizon. However, the formula works correctly only in conditions of a completely flat, for example, water surface. Formula for calculating the distance to the horizon: S = (R+h)2 - R21/2 In this formula: letter S the height of the observer's eyes in meters letter R the radius of the Earth is indicated, usually it is: 6367250 m letter h denotes the height of the observer's eyes above the surface in meters Using this formula, you can get a similar table. The visible horizon is often called the line along which the sky is seen bordering on the surface of the Earth. Also called the visible horizon and the celestial space above this boundary, and the surface of the Earth visible to man, and still the space visible to man, to its final limits. The distance to the visible horizon is calculated depending on the height of the observer above the earth's surface, and the radius of the earth is also taken into account in the calculation. The table shows the results of the calculations. There is even a special formula for calculating the distance to the horizon. And approximately we can say that if a person has an average height, then the horizon line from him is at a distance of approximately 5 kilometers. The higher you go, the farther the horizon line will be. So, for example, if you climb a lighthouse 20 meters high, you can observe the water surface at a distance of 17 kilometers. But on the Moon, a person of average height will be at a distance of 3.3 kilometers from the horizon line, and on Saturn already at 14.4 kilometers. The apparent distance to the horizon line depends on the terrain, but if we keep in mind that no objects block the horizon, for example, in the steppe or at sea, then objects are visible at 5 kilometers. This is if you look from the height of the growth of the average person. If a sailor climbs an eight-meter mast, he will be able to look at objects at a distance of 10 kilometers. From the television tower in Ostankino, the horizon will expand to 80 km, it is at this distance that there is a stable prim radio signal. From a plane flying at an altitude of 10 kilometers, a distance of 350 kilometers can already be seen, and astronauts from a space station in orbit can see up to 2 thousand kilometers. The horizon is visible and true, so the distance will be different if you put people on different points. If a person looks in a standing position, then approximately the distance is 5 km. If you climb a mountain 8 km high, then the distance to the horizon will be about 10 km. At an altitude of 10 thousand meters, the distance increases to 350 km. That is, everyone has a different distance to the horizon they see. On a flat area (water surface) about 6 km. The higher the viewpoint, the farther the horizon. If you mean the line of the visible horizon, then the distance to does not depend on the height of the observer's eyes. From the navigation bridge of the ship on which I had to serve, the horizon line was at a distance of 5 miles (1852 x 5 meters). Through the navigational periscope raised on the surface, the distance to the horizon line was already 11 miles ... Nothing at all. An hour of walking. It is very interesting to sit on the horizon, dangling legs and dangling them. You can, of course, climb the rainbow, only for this you need a ladder. And the horizon is right there. And you don't have to take anything with you. The visible horizon line also depends on the conditions of observation (weather, atmospheric phenomena, etc.). So, from the same point of view (for me, for example, an embankment on the high bank of the Volga), depending on visibility, a certain horizon is visible in the direction of water meadows, sometimes for 8-9, sometimes more than 30 kilometers. The distance to the horizon depends on many parameters. For example, from your vision. And even more important is the height at which you are. So, from Everest, the horizon will be visible at a distance of 336 kilometers. But from the lowland it can be seen even after 5 kilometers. Rice. 4 Basic lines and planes of the observer For orientation in the sea, a system of conditional lines and planes of the observer is adopted. On fig. 4 shows the globe, on the surface of which at the point M the observer is located. His eye is at the point BUT. letter e the height of the observer's eye above sea level. The line ZMn drawn through the place of the observer and the center of the globe is called a plumb or vertical line. All planes passing through this line are called vertical, and perpendicular to it - horizontal. The horizontal plane HH / passing through the observer's eye is called true horizon plane. The vertical plane VV / passing through the place of the observer M and the earth's axis is called the plane of the true meridian. At the intersection of this plane with the Earth's surface, a large circle РnQPsQ / is formed, called the true meridian of the observer. The straight line obtained from the intersection of the plane of the true horizon with the plane of the true meridian is called true meridian line or midday line N-S. This line defines the direction to the north and south points of the horizon. The vertical plane FF / perpendicular to the plane of the true meridian is called the plane of the first vertical. At the intersection with the plane of the true horizon, it forms the line E-W, perpendicular to the line N-S and defining the directions to the eastern and western points of the horizon. Lines N-S and E-W divide the plane of the true horizon into quarters: NE, SE, SW and NW. Fig.5. Horizon visibility range In the open sea, the observer sees a water surface around the ship, bounded by a small circle CC1 (Fig. 5). This circle is called the visible horizon. The distance De from the position of the vessel M to the line of the visible horizon CC 1 is called visible horizon. The theoretical range of the visible horizon Dt (segment AB) is always less than its actual range De. This is explained by the fact that, due to the different density of the layers of the atmosphere along the height, the beam of light does not propagate in it in a straight line, but along the AC curve. As a result, the observer can additionally see some part of the water surface located behind the line of the theoretical visible horizon and limited by a small circle SS 1 . This circle is the line of the visible horizon of the observer. The phenomenon of refraction of light rays in the atmosphere is called terrestrial refraction. Refraction depends on atmospheric pressure, temperature and humidity. In the same place on the Earth, refraction can change even during one day. Therefore, in the calculations, the average value of refraction is taken. Formula for determining the range of the visible horizon: As a result of refraction, the observer sees the horizon line in the direction AC / (Fig. 5), tangent to the AC arc. This line is raised at an angle r above the direct line AB. Injection r also called terrestrial refraction. Injection d between the plane of the true horizon HH / and the direction to the visible horizon is called apparent horizon inclination. RANGE OF VISIBILITY OF OBJECTS AND LIGHTS. The range of the visible horizon allows you to judge the visibility of objects located at the water level. If an object has a certain height h above sea level, then the observer can detect it at a distance: On nautical charts and in navigational aids, a pre-calculated range of visibility of lighthouse lights is given. Dk from the observer's eye height of 5 m. From this height De equals 4.7 miles. At e other than 5 m should be corrected. Its value is: Then the visibility range of the beacon Dn is equal to: The range of visibility of objects, calculated according to this formula, is called geometric, or geographical. The calculated results correspond to some average state of the atmosphere in the daytime. In fog, rain, snowfall or foggy weather, the visibility of objects naturally decreases. On the contrary, under a certain state of the atmosphere, the refraction can be very large, as a result of which the visibility range of objects turns out to be much greater than the calculated one. Visible horizon distance. Table 22 MT-75: The table is calculated by the formula: De = 2.0809 , Entering the table 22 MT-75 with item height h above sea level, get the visibility range of this object from sea level. If we add to the obtained range the range of the visible horizon found in the same table according to the height of the observer's eye e above sea level, then the sum of these distances will be the visibility range of the object, without taking into account the transparency of the atmosphere. To get the range of the radar horizon Dr. accepted selected from the table. 22 increase the range of the visible horizon by 15%, then Dp=2.3930 . This formula is valid for standard atmospheric conditions: pressure 760 mm, temperature +15°C, temperature gradient - 0.0065 degrees per meter, relative humidity, constant with altitude, 60%. Any deviation from the accepted standard state of the atmosphere will cause a partial change in the range of the radar horizon. In addition, this range, i.e. the distance from which reflected signals can be seen on the radar screen, depends to a large extent on the individual characteristics of the radar and the reflective properties of the object. For these reasons, use the coefficient 1.15 and the data in Table. 22 should be followed with caution. The sum of the ranges of the radar horizon of the antenna Ld and the observed object of height A will be the maximum distance from which the reflected signal can return. Example 1
Determine the detection range of the beacon with height h=42 m from sea level from the height of the observer's eye e=15.5 m. The visibility range of an object can also be determined by the nomogram placed on the insert (Appendix 6). MT-75 Example 2
Find the radar range of an object with height h=122 m, if the effective height of the radar antenna Hd = 18.3 m above sea level. |
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